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Vol 10 Chapter 87: SpecificHeatCapaci…

Chapter 087 SpecificHeatCapacity

That's right, according to Joule's law Q=I2Rt, it can be concluded that if 100A current is output per second, then there will be Q=10000×R, which is 10KA current.

But the premise is that R is not air, and when R is air, the air resistivity is infinite, and in the case of arc discharge and gas ionization, the 10,000A current will disappear like a drop of fresh water entering the sea.

Could it be that the electronic cycle device has solved this problem?

According to Joule's law Q=I2Rt, it can be concluded that if 100A current is output per second, then there is Q=10000×R, which is 10KA current.

But the premise is that R is not air, and when R is air, the air resistivity is infinite, and in the case of arc discharge and gas ionization, the 10,000A current will disappear like a drop of fresh water entering the sea.

Could it be that the electronic cycle device has solved this problem?

Thinking of this, Zhou Wenwen carefully observed the electronic cycle device again. He found that the electronic cycle device can mix αβ energy and electrons and emit them, and can also absorb 0.001 degrees of αβ energy and 1A current in the energy system every second, the maximum Output 30KL.

These absorbed αβ energy and current will enter the accelerator tube along the superconductor, and after circulating for 1 week, they will be mixed into 1L of ash energy, and then enter the accelerator transmitter for emission.

But it does not mean that the formula that 0.001ав+1I is equal to 1L will hold.

And the correct formula should be...

Thinking of this, Zhou Wenwen quickly found a piece of paper and wrote on it in order:

△=ав?I.

t△? =.

Among them, is the unknown.

? It is to stir, to mix.

t is time, and we know 168 seconds.

? stands for unknown.

But the process of this formula is tortuous and long. Zhou Wenwen believes that his third grade level will definitely not be able to supplement this formula. When he sees Iron Man, he may be able to chat with him.

Zhou Wenwen turned his head and thought, as the saying goes, practice brings true knowledge, Zhou Wenwen can first try the 1L unit of ashes energy, how powerful it is.

Thinking of this, Zhou Wenwen's interest suddenly increased. He pressed the button of the armor on his left hand to take over the αβ electron absorption cycle to convert and emit the ash energy 0.1 system. He called up 3 degrees of αβ energy and 10A current, and quickly introduced it into the acceleration tube to circulate it.

The time setting is to fire after the time reaches 1 second.

So after more than 2 minutes, that is, 168 seconds and 1 second later, a white energy beam shot out from the mouth of the electronic circulation device, and within 3 seconds, it hit the rear armor of the pickup truck, which was 5 meters away from Zhou Wenwen.

The tail armor of the pickup immediately left the tail of the pickup, and flew more than 50 meters within 6 seconds before falling. The hunter's survey showed that it was 57.21 meters.

After getting the value, Zhou Wenwen began to calculate, first according to the formula t△? = This first value formula will yield:

1× This second value formula, since 0.001 degrees ав+1A is equal to 1L, import the second value formula and solve it to get: 1×3+1×10? +2.997ав=30L∝2.997ав.

∝ stands for surplus, package, and the known Q=I2Rt, the unit of Q is J, that is, joule, which is the unit of energy and work, 1 joule of energy is equal to 1 Newton The action point of the force moves a distance of 1 meter in the direction of the force work done.

Then substitute 30L∝2.997ав into the formula of I2R, and the third value formula of Q=30L∝2.997ав×t will be obtained.

In view of the fact that the tail armor of the pickup truck flew out 57.21 meters, import the third value formula and solve it to get:

57.21Q=30∝2.997ав×t is the fourth value formula.

It is also known that the time for the pickup truck tail armor to fly out is 6.72, and the fourth value formula is imported to solve it and we can get:

57.21=30∝2.997ав×6.72

Simplify to get:

8.51339286=4.46428571∝0.445982143ав×1 This fifth value formula.

So what is the use of this 5th value formula? Is it correct?

Zhou Wenwen didn't know the answer, but he knew that the fifth value formula could be used as a comparison.

Zhou Wenwen took a deep breath, and pressed the button on the left arm armor again to take over the αβ electron absorption cycle, convert the ash energy 0.1 system, call up 15 degrees of αβ energy and 18A current, and introduce it into the acceleration tube to circulate.

If the time is still set, it will be launched after the time reaches 1 second.

In this way, after 168 seconds and 1 second, a not thick white energy beam shot out from the nozzle of the electronic cycle device with a bang, and hit the front of the pickup straight, and then an unexpected thing happened. .

The front of the pickup did not fly out like the rear armor of the pickup, but melted a small hole and exploded immediately. Obviously, the energy beam penetrated the oil pipe of the front of the pickup, and the high temperature ignited the gasoline. produce an explosion.

So how to calculate this second example?

Thinking of this, Zhou Wenwen couldn't help falling into contemplation.

Zhou Wenwen knows that under normal atmospheric pressure, the spontaneous ignition point of gasoline is 427°C.

However, gasoline volatilizes quickly, and gasoline vapor is easily ignited when mixed with air, which will also cause the flash point of gasoline to be lower than about 28°. Generally, the lower the flash point, the higher the auto-ignition point.

The flash point is the temperature at which the oil can flash when it encounters an open flame when it is heated to a certain temperature.

To be on the safe side, Zhou Wenwen preliminarily estimated that after the energy beam penetrated the oil pipe ~www.wuxiamtl.com~ when the gasoline and the air were fused, the energy beam with a surface temperature of at least 20 degrees ignited the gasoline and eventually exploded.

Apart from gasoline, the key now is an energy beam with a surface temperature of at least 20 degrees.

And this involves the specific heat capacity.

Specific heat capacity, English abbreviation SHC, English full name SpecificHeatCapacity, symbol c.

SHC, referred to as specific heat, also known as specific heat capacity, is a physical quantity commonly used in thermodynamics, used to express the ability of a substance to absorb or dissipate heat.

Generally, the larger the specific heat capacity, the stronger the material's ability to absorb or dissipate heat.

The amount of heat absorbed per unit mass of a substance to raise its unit temperature.

The unit in the International System of Units is joules per kilogram Kelvin or joules per kilogram per degree Celsius, where J refers to joules and K refers to the thermodynamic temperature scale, that is, the energy required to raise the temperature of 1 kilogram of matter by 1 Kelvin.

And according to this theorem, the most basic formula can be derived as follows:

c=Q/m

Q is the heat absorbed, m is the mass of the object, and T is the change in temperature after the heat is absorbed.

It is known that the temperature is 20 degrees, the specific heat capacity of pickup gasoline is about 0.8 to 1.8, the minimum value of pickup gasoline oil pipe is 1 liter, and the maximum is 6 liters. Four formulas can be obtained by importing the formula:

0.8=20/1, 0.8=20/6.

......

To be continued

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Chapter 088 Announcement of Hydra's Base

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